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On this day: Lasit Malinga takes 4 wickets in 4 balls against South Africa

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Image source: TWITTER / MUMBAIINDIANS

Lasit Malinga

Lasit Malinga sent shivers down the spine of the South Africans on March 28, 2007 in a Super Eight match at the 2007 World Cup, when he took four consecutive wickets towards the end of their inning.

South Africa was heading for what could be a winning victory when Malinga started bowling 45th. All of Sri Lanka were out for just 209 runs, and South Africa was 200/5 at the start with legendary universalists Jacques Kalis and Sean Pollock in the middle. Kalis was 85 out of 108 balls until Pollock took the time to get in his eye, scoring seven 19-ball runs.

Pollock hit four of the second ball on over and then took two of the fourth to reduce the deficit to four runs required by 32 balls. That was when Malinga began weaving her magic into the match.

He first fired Pollock with a slower ball, then made Andrew Hall hide with a yorker from the last ball over. Then Chaminda Vaas gave only one run in the next, after which Malinga returned to take down Kalis from the first ball of the 47th.

That ended his hat trick, but it wasn’t over yet. Malinga threw himself into another scorching Yorker at Mahaya Ntini, who missed him completely and the ball hit the stumps. South Africa went from 206/5 to 208/9 and moved from a comfort position to losing the match in two shots.

Malinga would make five out of five, as well as beat Charles Langeveldt’s outside with another Yorker-length delivery on the next ball. The South Africans somehow survived the next one before Robin Petersen hit a four from Malinga in the 49th to take the protests over the line.

Malinga will repeat the feat more than a decade later in the T20I against New Zealand in 2019. This time, however, it was the start of Kiwis’ inning and as a result, everyone was out for 88, despite chasing a goal of 126.

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